A bank tells a real estate agent that average closing costs on the sale of a home are $6500. The agent thinks that this is too low an estimate so she randomly selects 20 recent home sales and finds that the average closing costs are $6550 with a sample standard deviation of $120 and that the closing costs appear to be normally distributed.
The null hypothesis would be rejected at the 伪 = 0.05 level..
True
False(Question Below) True or False?
Given the following data:
渭o = 6500
n = 20
X-bar = 6550
s = 120
伪 = 0.05
The hypotheses are:
Ho: 渭 = 6500
H1: 渭 %26gt; 6500
The population variance is unknown and the sample size small. Therefore the appropriate test statistic is the t-test:
T = (X-bar - 渭o) / s/鈭歯
T = (6550 - 6500) / 120/鈭?0
T = 1.863
The critical t-value corresponding to 伪 = 0.05 and (n-1) degrees of freedom is 1.729.
Since the test statistic exceeds the critical t-value, we reject the null hypothesis.(Question Below) True or False?
Do you know what the null hypothesis is? What DO you know about this problem. don't just ask the question - you won't leran anything from that.
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